The angle of elevation of the top of an unfin | vedclass

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(B) Let the initial height of the tower be $h$ and the additional height required be $x$. The distance from the base is $120 \ m$.From the first condi

Vedclass · Accepted Answer

$120(\sqrt{3}-1) \ m$

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(B) Let the initial height of the tower be $h$ and the additional height required be $x$. The distance from the base is $120 \ m$.From the first condition,the angle of elevation is $45^{\circ}$:$	an 45^{\circ} = \frac{h}{120}$$1 = \frac{h}{120} \implies h = 120 \ m$.From the second condition,the angle of elevation of the new top is $60^{\circ}$:$	an 60^{\circ} = \frac{h+x}{120}$$\sqrt{3} = \frac{120+x}{120}$$120\sqrt{3} = 120 + x$$x = 120\sqrt{3} - 120$$x = 120(\sqrt{3}-1) \ m$.Thus,the tower must be raised by $120(\sqrt{3}-1) \ m$.

The angle of elevation of the top of an unfinished tower at a point distant $120 \ m$ from its base is $45^{\circ}$. If the elevation of the top at the same point is to be $60^{\circ}$,the tower must be raised to a height of:

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