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(C) Let the angles of the quadrilateral be $3x$,$4x$,$6x$,and $5x$.We know that the sum of the angles of a quadrilateral is $360^\circ$.Therefore,$3x

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$120$

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(C) Let the angles of the quadrilateral be $3x$,$4x$,$6x$,and $5x$.We know that the sum of the angles of a quadrilateral is $360^\circ$.Therefore,$3x + 4x + 6x + 5x = 360^\circ$.$18x = 360^\circ$.$x = \frac{360^\circ}{18} = 20^\circ$.The angles are:$3 	imes 20^\circ = 60^\circ$$4 	imes 20^\circ = 80^\circ$$6 	imes 20^\circ = 120^\circ$$5 	imes 20^\circ = 100^\circ$.The greatest angle is $120^\circ$.

The angles of a quadrilateral are in the ratio $3:4:6:5$. Find the measure of the greatest angle. (in $^\circ$)

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