The area (in square units) of the circle whic | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given lines are $4x + 3y - 15 = 0$ and $4x + 3y - 5 = 0$. Since these lines are parallel,the distance $d$ between them is the diameter of the

Vedclass · Accepted Answer

$\pi$

Vedclass · Answer

(D) The given lines are $4x + 3y - 15 = 0$ and $4x + 3y - 5 = 0$. Since these lines are parallel,the distance $d$ between them is the diameter of the circle.$d = \frac{|c_1 - c_2|}{\sqrt{a^2 + b^2}} = \frac{|-15 - (-5)|}{\sqrt{4^2 + 3^2}} = \frac{|-10|}{\sqrt{16 + 9}} = \frac{10}{5} = 2$.Since the diameter $d = 2$,the radius $r = \frac{d}{2} = 1$.The area of the circle is $\pi r^2 = \pi(1)^2 = \pi 	ext{ square units}$.

The area (in square units) of the circle which touches the lines $4x + 3y = 15$ and $4x + 3y = 5$ is

Similar Questions

Wind pollination is common in . . . . . . .

$A$ particle moves along the curve $y=x^2+2x$. The point on the curve such that the $x$ and $y$ coordinates of the particle change at the same rate is

If the lines $4x + 3y - 1 = 0$,$x - y + 5 = 0$,and $kx + 5y - 3 = 0$ are concurrent,then $k$ is equal to:

Explain competition in detail.

When acetaldehyde is heated with Fehling solution,a red precipitate is formed. Which of the following is that?

Vedclass Test Series

Exam Paper Generator

Online Exam Module