(B) The area $A$ bounded by the curve $y = \sin x$,the $x$-axis,and the lines $x = 0$ and $x = \pi$ is given by the definite integral:$A = \int_{0}^{\

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(B) The area $A$ bounded by the curve $y = \sin x$,the $x$-axis,and the lines $x = 0$ and $x = \pi$ is given by the definite integral:$A = \int_{0}^{\pi} |\sin x| \, dx$Since $\sin x \geq 0$ for $x \in [0, \pi]$,we have:$A = \int_{0}^{\pi} \sin x \, dx$$A = [-\cos x]_{0}^{\pi}$$A = -(\cos \pi - \cos 0)$$A = -(-1 - 1)$$A = -(-2) = 2$Thus,the area is $2$ square units.

Class 12 Mathematics Application of Integration Area bounded by region of single curve

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The area bounded by the $x$-axis and the curve $y = \sin x$ between $x = 0$ and $x = \pi$ is:

A
$1$
B
$2$
C
$3$
D
$4$

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Application of Integration

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Area bounded by region of single curve

The area of the region bounded by the curve $y=x|x|$,lines $x=-1$ and $x=1$ is . . . . . . .

EasyGSEB 2024

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MediumAP EAMCET 2023

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DifficultMHT CET 2026

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The area of the region lying in the first quadrant and bounded by the curve $y = 4x^2$, the $Y$-axis, and the lines $y = 2$ and $y = 4$ is:

DifficultMHT CET 2026

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Area enclosed by the parabola $ay = 3(a^2 - x^2)$ and $x$-axis is

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The area bounded by the $x$-axis and the curve $y = \sin x$ between $x = 0$ and $x = \pi$ is:

Similar Questions

The area of the region bounded by the curve $y=x|x|$,lines $x=-1$ and $x=1$ is . . . . . . .

The area bounded by the curve $x=\log (|y|)$,the lines $x=-1$ and $x=0$ is

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