The area of odot(O, r) is 240 , cm^2. In odot | vedclass

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(A) The area of the circle $\odot(O, r)$ is given as $\pi r^2 = 240 \, cm^2$.The formula for the area of a sector with central angle $	heta$ is $	ex

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(A) The area of the circle $\odot(O, r)$ is given as $\pi r^2 = 240 \, cm^2$.The formula for the area of a sector with central angle $	heta$ is $	ext{Area} = \frac{	heta}{360^\circ} 	imes \pi r^2$.Given $	heta = 45^\circ$ and $\pi r^2 = 240 \, cm^2$,we substitute these values into the formula:$	ext{Area of minor sector } OACB = \frac{45}{360} 	imes 240$$	ext{Area of minor sector } OACB = \frac{1}{8} 	imes 240 = 30 \, cm^2$.Therefore,the area of the minor sector is $30 \, cm^2$.

The area of $\odot(O, r)$ is $240 \, cm^2$. In $\odot(O, r)$,minor arc $\widehat{ACB}$ subtends an angle of measure $45^\circ$ at the centre. Then,the area of minor sector $OACB$ is $\dots \dots \dots \, cm^2$.

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