Class 11MathematicsTrigonometrical EquationsRelation between sides and angles, Solutions of triangles
MediumThe area of a $\Delta ABC$ is equal to
- A$\frac{1}{2}ab \sin C$
- B$\frac{1}{2}bc \sin A$
- C$\frac{1}{2}ca \sin B$
- D$bc \sin A$
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Similar Questions
In any triangle $ABC$,$a \cdot \cos^2 \frac{A}{2} + b \cdot \cos^2 \frac{B}{2} + c \cdot \cos^2 \frac{C}{2} =$
In a $\Delta ABC$,if $A = 30^o$,$b = 2$,and $c = \sqrt{3} + 1$,then $\frac{C - B}{2} = $ ....$^o$
Medium
View SolutionIn a $\triangle ABC$,if $\angle C = 90^{\circ}$,then $\frac{a^2-b^2}{a^2+b^2}$ is equal to
DifficultAP EAMCET 2010
View SolutionIn $\triangle ABC$,if $A=75^{\circ}$ and $B=45^{\circ}$,then the value of $b+c\sqrt{2}$ is:
In a $\Delta ABC$,the expression $\frac{\cos C + \cos A}{c + a} + \frac{\cos B}{b}$ is equal to:
Easy
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