(D) The side of the square is $\sqrt{1024\, cm^2} = 32\, cm$.The length of the rectangle is $2 \times 32\, cm = 64\, cm$.The breadth of the rectangle

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(D) The side of the square is $\sqrt{1024\, cm^2} = 32\, cm$.The length of the rectangle is $2 \times 32\, cm = 64\, cm$.The breadth of the rectangle is $32\, cm - 12\, cm = 20\, cm$.The required ratio of length to breadth is $64 : 20$.Dividing both terms by $4$,we get $16 : 5$.

Competitive Quantitative Aptitude Mensuration Measurement of Area

Medium

The area of a square is $1024\, cm^2$. What is the ratio of the length to the breadth of a rectangle whose length is twice the side of the square and breadth is $12\, cm$ less than the side of this square?

A
$5:18$
B
$16:7$
C
$14:5$
D
$16:5$

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Measurement of Area

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The area of a square is $1024\, cm^2$. What is the ratio of the length to the breadth of a rectangle whose length is twice the side of the square and breadth is $12\, cm$ less than the side of this square?

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If the area of an equilateral triangle is equal to the area of an isosceles triangle whose base and equal sides are $16 \, cm$ and $10 \, cm$ respectively,then the side of the equilateral triangle is......$cm$

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In the given figure, $ABCDEF$ is a regular hexagon whose side is $6\, cm$. $APF$, $QAB$, $DCR$, and $DES$ are equilateral triangles. What is the area (in $cm^2$) of the shaded region (in $\sqrt{3}$)?

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