The area of the hole of a heat furnace is 10^ | vedclass

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(C) According to Stefan-Boltzmann law,the power radiated is given by $P = \sigma \varepsilon A T^4$.Here,$P = \frac{1.58 	imes 10^5 \ cal}{1 \ hour}

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$2500$

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(C) According to Stefan-Boltzmann law,the power radiated is given by $P = \sigma \varepsilon A T^4$.Here,$P = \frac{1.58 	imes 10^5 \ cal}{1 \ hour} = \frac{1.58 	imes 10^5 	imes 4.2 \ J}{3600 \ s} \approx 184.33 \ W$.Given: $A = 10^{-4} \ m^2$,$\varepsilon = 0.80$,$\sigma = 5.67 	imes 10^{-8} \ W/m^2K^4$.Substituting the values: $184.33 = 5.67 	imes 10^{-8} 	imes 0.80 	imes 10^{-4} 	imes T^4$.$T^4 = \frac{184.33}{5.67 	imes 0.80 	imes 10^{-12}} \approx 4.06 	imes 10^{13} \approx 3906250000000$.Taking the fourth root,$T \approx 2500 \ K$.

The area of the hole of a heat furnace is $10^{-4} \ m^2$. It radiates $1.58 \times 10^5 \ cal$ of heat per hour. If the emissivity of the furnace is $0.80$,then its temperature is .......... $K$.

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