The area of the region bounded by the curves $y = \sin x$, $y = \cos x$ and the lines $x = 0$, $x = \frac{\pi}{4}$ is

  • A
    $\sqrt{2} - 1$
  • B
    $1 - \frac{1}{\sqrt{2}}$
  • C
    $\sqrt{2} + 1$
  • D
    $2 - \sqrt{2}$

Explore More

Similar Questions

The area of the region bounded by the curve $y = 2^{kx}$ and the lines $x = 0$ and $x = 2$ in the first quadrant is $\frac{2}{\log_e 2}$. Find the value of $k$.

The area of the region bounded by the curve $y=2x-x^2$ and the $x$-axis is

The area (in square units) bounded by the line $y = x$, the $X$-axis and the lines $x = -2$ and $x = 4$ is...

The area enclosed between the curves $y=x|x|$ and $y=x-|x|$ is :

The area bounded by the curve $xy = c$,the $x$-axis,and the lines $x = 1$ and $x = 4$ is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo