The area of the triangle enclosed by the stra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given lines are $x = 0$ (y-axis),$y = 0$ (x-axis),and $x + 2y + 3 = 0$.To find the vertices of the triangle,we find the intersection points:$1

Vedclass · Accepted Answer

$2.25$

Vedclass · Answer

(B) The given lines are $x = 0$ (y-axis),$y = 0$ (x-axis),and $x + 2y + 3 = 0$.To find the vertices of the triangle,we find the intersection points:$1$. Intersection of $x = 0$ and $y = 0$ is $(0, 0)$.$2$. Intersection of $x = 0$ and $x + 2y + 3 = 0$: Substituting $x = 0$,we get $2y = -3$,so $y = -1.5$. The point is $(0, -1.5)$.$3$. Intersection of $y = 0$ and $x + 2y + 3 = 0$: Substituting $y = 0$,we get $x = -3$. The point is $(-3, 0)$.The triangle is a right-angled triangle with base length $|-3| = 3$ and height $|-1.5| = 1.5$.Area $= \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes 3 	imes 1.5 = \frac{4.5}{2} = 2.25$ sq. units.

The area of the triangle enclosed by the straight lines $x = 0$,$y = 0$ and $x + 2y + 3 = 0$ in sq. units is:

Similar Questions

The area of the parallelogram formed by the lines $y = mx, y = mx + 1, y = nx, y = nx + 1$ is:

The equations of two altitudes of an equilateral triangle are $\sqrt{3}x - y + 8 - 4\sqrt{3} = 0$ and $\sqrt{3}x + y - 12 - 4\sqrt{3} = 0$. The equation of the third altitude is

The sides of a quadrilateral are all positive integers and three of them are $5, 10, 20$. How many possible values are there for the fourth side?

Two equal sides of an isosceles triangle are given by $7x-y+3=0$ and $x+y-3=0$. If the slope $m$ of the third side is an integer,then $m=$

Let $A(h, k)$,$B(1, 1)$,and $C(2, 1)$ be the vertices of a right-angled triangle with $AC$ as the hypotenuse. If the area of the triangle is $1$,then which of the following can be the set of values for $k$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module