The areas of two similar triangles are 25 and | vedclass

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(B) For two similar triangles,the ratio of their areas is equal to the square of the ratio of their corresponding sides.Let the areas be $A_1 = 25$ an

Vedclass · Accepted Answer

$5: 4$

Vedclass · Answer

(B) For two similar triangles,the ratio of their areas is equal to the square of the ratio of their corresponding sides.Let the areas be $A_1 = 25$ and $A_2 = 16$.Let the corresponding sides be $s_1$ and $s_2$.Then,$\frac{A_1}{A_2} = (\frac{s_1}{s_2})^2$.$\frac{25}{16} = (\frac{s_1}{s_2})^2$.Taking the square root on both sides,$\frac{s_1}{s_2} = \sqrt{\frac{25}{16}} = \frac{5}{4}$.The ratio of the perimeters of two similar triangles is equal to the ratio of their corresponding sides.Therefore,the ratio of their perimeters is $5: 4$.

The areas of two similar triangles are $25$ and $16$. Then,the ratio of their perimeters is $\ldots \ldots \ldots \ldots$

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