The average e.m.f. induced in a coil in which | vedclass

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(B) The formula for the induced $e.m.f.$ in a coil due to self-induction is given by $e = -L \frac{di}{dt}$.Here,the magnitude of the induced $e.m.f.$

Vedclass · Accepted Answer

$0.2$

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(B) The formula for the induced $e.m.f.$ in a coil due to self-induction is given by $e = -L \frac{di}{dt}$.Here,the magnitude of the induced $e.m.f.$ is $|e| = 8 \,V$.The change in current is $di = 2 \,A - 0 \,A = 2 \,A$.The time interval is $dt = 0.05 \,s$.Substituting these values into the formula: $8 = L 	imes \frac{2}{0.05}$.$8 = L 	imes 40$.$L = \frac{8}{40} = 0.2 \,H$.Therefore,the self-inductance of the coil is $0.2 \,H$.

The average $e.m.f.$ induced in a coil in which a current changes from $0$ to $2 \,A$ in $0.05 \,s$ is $8 \,V.$ The self-inductance of the coil is:

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