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(C) The intensity of a sound wave is directly proportional to the square of its amplitude,i.e.,$I \propto A^2$.When two sound sources of the same ampl

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Four times

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(C) The intensity of a sound wave is directly proportional to the square of its amplitude,i.e.,$I \propto A^2$.When two sound sources of the same amplitude $a_0$ interfere,the maximum amplitude $A_{\max}$ produced during the formation of beats is the sum of the individual amplitudes: $A_{\max} = a_0 + a_0 = 2a_0$.The maximum intensity $I_{\max}$ is then given by $I_{\max} \propto (A_{\max})^2 = (2a_0)^2 = 4a_0^2$.Since the intensity of one source is $I_0 \propto a_0^2$,we have $I_{\max} = 4I_0$.Therefore,the maximum intensity of beats is $4$ times that of one source.

The beats are produced by two sound sources of same amplitude and of nearly equal frequencies. The maximum intensity of beats will be ...... that of one source.

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