The best explanation for the solubility of $MnS$ in dil. $HCl$ is that
- ASolubility product of $MnCl_2$ is less than that of $MnS$
- BConcentration of $Mn^{2+}$ is lowered by the formation of complex ions with chloride ions
- CConcentration of sulphide ions is lowered by oxidation to free sulphur
- DConcentration of sulphide ions is lowered by formation of the weak acid $H_2S$
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View SolutionThe solubility products of three sparingly soluble salts $AB$,$A_2B$ and $AB_3$ are respectively $4.0 \times 10^{-20}$,$3.2 \times 10^{-11}$ and $2.7 \times 10^{-31}$. The increasing order of their solubility is
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View SolutionMatch the following metal sulfides with their respective solubility product $(K_{sp})$ values:
Metal sulfide Solubility product $A$. $PbS$ $I$. $4.0 \times 10^{-53}$ $B$. $HgS$ $II$. $8.0 \times 10^{-28}$ $C$. $MnS$ $III$. $1.6 \times 10^{-24}$ $D$. $ZnS$ $IV$. $2.5 \times 10^{-13}$
| Metal sulfide | Solubility product |
|---|---|
| $A$. $PbS$ | $I$. $4.0 \times 10^{-53}$ |
| $B$. $HgS$ | $II$. $8.0 \times 10^{-28}$ |
| $C$. $MnS$ | $III$. $1.6 \times 10^{-24}$ |
| $D$. $ZnS$ | $IV$. $2.5 \times 10^{-13}$ |
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