The binding energy per nucleon is maximum in the case of

The energy equivalent of $1 \,g$ of substance is:

The equivalent energy of a mass equal to $1 \, a.m.u.$ is

Deuteron is a bound state of a neutron and a proton with a binding energy $B = 2.2 \, MeV$. $A$ $\gamma$-ray of energy $E$ is aimed at a deuteron nucleus to try to break it into a (neutron + proton) such that the $n$ and $p$ move in the direction of the incident $\gamma$-ray. If $E = B$,show that this cannot happen. Hence,calculate how much bigger than $B$ must $E$ be for such a process to happen.

Let ${m_p}$ be the mass of a proton,${m_n}$ the mass of a neutron,${M_1}$ the mass of a $_{10}^{20}Ne$ nucleus,and ${M_2}$ the mass of a $_{20}^{40}Ca$ nucleus. Then:

$A$ heavy nucleus having mass number $200$ gets disintegrated into two small fragments of mass numbers $80$ and $120$. If binding energy per nucleon for the parent atom is $6.5 \text{ MeV}$ and for the daughter nuclei is $7 \text{ MeV}$ and $8 \text{ MeV}$ respectively, then the energy released in the decay will be: (in $\text{ MeV}$)