The bob of a pendulum of length l is pulled a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When the pendulum bob is pulled aside by an angle $	heta$,it is raised to a vertical height $h$ above its equilibrium position.From the geometry

Vedclass · Accepted Answer

$\sqrt{2gl(1 - \cos 	heta)}$

Vedclass · Answer

(C) When the pendulum bob is pulled aside by an angle $	heta$,it is raised to a vertical height $h$ above its equilibrium position.From the geometry of the pendulum,the vertical height $h$ is given by $h = l - l \cos 	heta = l(1 - \cos 	heta)$.According to the law of conservation of mechanical energy,the potential energy at the highest point is converted into kinetic energy at the equilibrium position.$PE_{initial} = KE_{final}$$Mgh = \frac{1}{2} Mv^2$Substituting $h = l(1 - \cos 	heta)$:$Mg l(1 - \cos 	heta) = \frac{1}{2} Mv^2$$v^2 = 2gl(1 - \cos 	heta)$$v = \sqrt{2gl(1 - \cos 	heta)}$

The bob of a pendulum of length $l$ is pulled aside from its equilibrium position through an angle $\theta$ and then released. The bob will then pass through its equilibrium position with speed $v$,where $v$ equals

Similar Questions

$A$ simple pendulum of length $L$ swings in a vertical plane. The tension in the string when it makes an angle $\theta$ with the vertical and the bob of mass $m$ moves with a speed $v$ is (where $g$ is the gravitational acceleration):

The acceleration due to gravity on the surface of the moon is $1.7 \; m s^{-2}$. What is the time period of a simple pendulum on the surface of the moon if its time period (in $s$) on the surface of the earth is $3.5 \; s$? ($g$ on the surface of the earth is $9.8 \; m s^{-2}$)

The bob of a simple pendulum of length $l$ is made of iron. The pendulum is oscillating over a horizontal coil carrying a direct current. If the time period of the pendulum is $T$,then:

The length of a simple pendulum is increased by $44\%$. The percentage increase in its time period will be ..... $\%$

Two pendulums having lengths $1.0 \ m$ and $1.21 \ m$ start oscillating simultaneously in the same phase. They will again come in the same phase after how many oscillations of the smaller pendulum?

Vedclass Test Series

Exam Paper Generator

Online Exam Module