The boiling point (in K) of cis-but-2-ene and | vedclass

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(B) In the $cis-isomer$,the methyl groups are on the same side of the double bond,resulting in a net dipole moment.In the $trans-isomer$,the methyl gr

Vedclass · Accepted Answer

$277, 0.00$

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(B) In the $cis-isomer$,the methyl groups are on the same side of the double bond,resulting in a net dipole moment.In the $trans-isomer$,the methyl groups are on opposite sides,causing the individual bond dipoles to cancel each other out,resulting in a net dipole moment of $0.00 \ D$.Due to the higher polarity,the $cis-isomer$ has stronger intermolecular dipole-dipole interactions compared to the $trans-isomer$,leading to a higher boiling point.The boiling point of $cis-but-2-ene$ is $277 \ K$ and the dipole moment of $trans-but-2-ene$ is $0.00 \ D$.

The boiling point (in $K$) of $cis-but-2-ene$ and dipole moment (in $D$) of $trans-but-2-ene$ are respectively:

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