The bond between carbon atom $(1)$ and carbon atom $(2)$ in compound $N \equiv C - CH = CH_2$ involves the hybridised carbon as

Allyl cyanide contains $9\sigma$ and $3\pi$ bonds.

Amongst the given options,the compound$(s)$ in which all the atoms are in one plane in all the possible conformations (if any),is (are):
$(A)$ $CH_2=CH-CH=CH_2$
$(B)$ $HC\equiv C-CH=CH_2$
$(C)$ $H_2C=C=O$
$(D)$ $H_2C=C=CH_2$

What are the hybridisation states of each carbon atom in the following compounds?
$CH_2=C=O, \quad CH_3-CH=CH_2, \quad (CH_3)_2CO, \quad CH_2=CH-CN, \quad C_6H_6$

Explain how the electronegativity of carbon atoms is related to their state of hybridization in an organic compound.

The total number of $C-C$ sigma $(\sigma)$ bonds in mesityl oxide $(C_6H_{10}O)$ is $......$. (Round off to the nearest integer).