The capacitive reactance of a capacitor C is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The formula for capacitive reactance is $X_C = \frac{1}{2 \pi f C}$.Given,the initial capacitive reactance is $X_C = X \ \Omega$.So,$X = \frac{1}{

Vedclass · Accepted Answer

$\frac{X}{4} \ \Omega$

Vedclass · Answer

(A) The formula for capacitive reactance is $X_C = \frac{1}{2 \pi f C}$.Given,the initial capacitive reactance is $X_C = X \ \Omega$.So,$X = \frac{1}{2 \pi f C}$.When the frequency is doubled $(f' = 2f)$ and the capacitance is doubled $(C' = 2C)$,the new capacitive reactance $X_C'$ is:$X_C' = \frac{1}{2 \pi f' C'} = \frac{1}{2 \pi (2f) (2C)}$.$X_C' = \frac{1}{4 (2 \pi f C)}$.Since $X = \frac{1}{2 \pi f C}$,we substitute this into the equation:$X_C' = \frac{X}{4} \ \Omega$.

The capacitive reactance of a capacitor $C$ is $X \ \Omega$. Both the frequency of the $A.C.$ supply and the capacitance of the capacitor are doubled. The new capacitive reactance will be:

Similar Questions

In the case of an inductor,

$(i)$ What is the angle between the phasor of $V_R$ and $I$?
$(ii)$ The voltage phasor $V_C$ is ...... of the current phasor $I$. (Fill in the blank)

Average power associated with an ideal inductor and ideal capacitor over a complete cycle of $a.c.$ is respectively

$A$ lamp is connected in series with a capacitor. Predict your observations for $dc$ and $ac$ connections. What happens in each case if the capacitance of the capacitor is reduced?

$A$ small signal voltage $V(t) = V_0 \sin(\omega t)$ is applied across an ideal capacitor $C$. Which of the following statements is correct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module