The Cartesian equation of the line passing through the point $(5, -2, 4)$ and parallel to the vector $3\hat{i}-2\hat{j}+8\hat{k}$ is . . . . . . .
- A$\frac{x-5}{3} = \frac{y+2}{-2} = \frac{z-4}{8}$
- B$\frac{x+5}{-3} = \frac{y-2}{2} = \frac{z+4}{8}$
- C$\frac{x+5}{3} = \frac{y-2}{-2} = \frac{z+4}{8}$
- D$\frac{x-5}{-3} = \frac{y+2}{2} = \frac{z-4}{8}$
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