The cell reaction Cu + 2Ag^{+} to Cu^{+2} + 2 | vedclass

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Question

(A) In a galvanic cell,the oxidation half-reaction occurs at the anode (left side) and the reduction half-reaction occurs at the cathode (right side).

Vedclass · Accepted Answer

$Cu_{(s)}|Cu^{+2}_{(aq)}||Ag^{+}_{(aq)}|Ag_{(s)}$

Vedclass · Answer

(A) In a galvanic cell,the oxidation half-reaction occurs at the anode (left side) and the reduction half-reaction occurs at the cathode (right side).The given reaction is: $Cu + 2Ag^{+} 	o Cu^{+2} + 2Ag$.Oxidation: $Cu_{(s)} 	o Cu^{+2}_{(aq)} + 2e^-$.Reduction: $2Ag^{+}_{(aq)} + 2e^- 	o 2Ag_{(s)}$.The cell notation is written as: $	ext{Anode} | 	ext{Anode electrolyte} || 	ext{Cathode electrolyte} | 	ext{Cathode}$.Therefore,the correct representation is $Cu_{(s)}|Cu^{+2}_{(aq)}||Ag^{+}_{(aq)}|Ag_{(s)}$.

The cell reaction $Cu + 2Ag^{+} \to Cu^{+2} + 2Ag$ is best represented by

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