The circle represented by the equation $x^2 + y^2 + 2gx + 2fy + c = 0$ will be a point circle,if

The equation of the circle whose end points of a diameter are the centres of the circles $x^{2}+y^{2}+2x-4y+1=0$ and $x^{2}+y^{2}-8x+6y+17=0$ is

The centre of the circle $r^2-4r(\cos \theta+\sin \theta)-4=0$ in Cartesian coordinates is

If $\theta$ is a parameter,then the parametric equations of the circle $x^{2}+y^{2}-6x+4y-3=0$ are given by

Let the circle $S: 36 x^{2}+36 y^{2}-108 x+120 y+C=0$ be such that it neither intersects nor touches the coordinate axes. If the point of intersection of the lines $x-2 y=4$ and $2 x-y=5$ lies inside the circle $S$,then :

The circle $x^2 + y^2 - 3x - 4y + 2 = 0$ cuts the $x$-axis at