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(D) Let the sides of the triangle be $a = 10$,$b = 8$,and $c = 6$.First,check if the triangle is a right-angled triangle by verifying the Pythagorean

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$5$

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(D) Let the sides of the triangle be $a = 10$,$b = 8$,and $c = 6$.First,check if the triangle is a right-angled triangle by verifying the Pythagorean theorem: $a^2 = b^2 + c^2$.$10^2 = 100$ and $8^2 + 6^2 = 64 + 36 = 100$.Since $100 = 100$,the triangle is a right-angled triangle with the hypotenuse $a = 10$.The circumradius $R$ of a right-angled triangle is half of its hypotenuse.$R = \frac{	ext{hypotenuse}}{2} = \frac{10}{2} = 5 \ units$.

The circumradius of a triangle whose sides are $10 \ units$,$8 \ units$,and $6 \ units$ is (in $units$)

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