The coach of a cricket team buys $3$ bats and $6$ balls for ₹ $3900$. Later,she buys another bat and $3$ more balls of the same kind for ₹ $1300$. Represent this situation algebraically and geometrically.

(N/A) Let the cost of a bat be ₹ $x$ and the cost of a ball be ₹ $y$.
According to the problem,the algebraic representation is:
$3x + 6y = 3900$
$x + 3y = 1300$
For the first equation,$3x + 6y = 3900$,we can simplify it to $x + 2y = 1300$,so $x = 1300 - 2y$.
| $x$ | $300$ | $100$ | $-100$ |
| $y$ | $500$ | $600$ | $700$ |
For the second equation,$x + 3y = 1300$,we have $x = 1300 - 3y$.
| $x$ | $400$ | $700$ | $1000$ |
| $y$ | $300$ | $200$ | $100$ |
The geometric representation is shown in the provided graph.