The coefficient of static friction between th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The necessary centripetal force for a car on a curved unbanked road is provided by the static friction force between the tyres and the road.For sa

Vedclass · Accepted Answer

$25 \,m$

Vedclass · Answer

(B) The necessary centripetal force for a car on a curved unbanked road is provided by the static friction force between the tyres and the road.For safe turning,the centripetal force must be less than or equal to the maximum static friction force:$\frac{mV^2}{r} \leq \mu mg$To find the maximum radius $r$ for a given speed $V$,we use the limiting case:$\frac{mV^2}{r} = \mu mg$$r = \frac{V^2}{\mu g}$Given values are $V = 10 \,ms^{-1}$,$\mu = 0.4$,and $g = 10 \,ms^{-2}$.Substituting these values into the equation:$r = \frac{10^2}{0.4 	imes 10}$$r = \frac{100}{4}$$r = 25 \,m$Thus,the maximum radius of curvature is $25 \,m$.

The coefficient of static friction between the road and tyres of a car is $0.4$. The maximum permissible speed of the car is $10 \,ms^{-1}$ on a curved unbanked road. Then the maximum radius of curvature of the road is (acceleration due to gravity $= 10 \,ms^{-2}$)

Similar Questions

$A$ car is moving on a circular track banked at an angle of $45^{\circ}$. If the maximum permissible speed of the car to avoid slipping is twice the optimum speed of the car to avoid the wear and tear of the tyres, then the coefficient of static friction between the wheels of the car and the road is

How is centripetal force provided while taking a turn on a level circular track?

$A$ particle is moving along the circle $x^2 + y^2 = a^2$ in an anticlockwise direction. The $x-y$ plane is a rough horizontal stationary surface. At the point $(a \cos \theta, a \sin \theta)$,the unit vector in the direction of friction on the particle is:

The maximum speed of a car on a road turn of radius $30\,m$; if the coefficient of friction between the tyres and the road is $0.4$; will be ........ $m/s$. (in $.84$)

$A$ train runs along an unbanked circular track of radius $30 \; m$ at a speed of $54 \; km/h$. The mass of the train is $10^{6} \; kg$. What provides the centripetal force required for this purpose - the engine or the rails? What is the angle of banking required to prevent wearing out of the rail?

Vedclass Test Series

Exam Paper Generator

Online Exam Module