The colour of $CuCr_2O_7$ solution in water is green because

Match the following:

Column-$1$ (Reaction)	Column-$2$ (Main product)
$A$. $4FeCl_3 + 3K_4[Fe(CN)_6] \rightarrow$	$I$. $Fe_4[Fe(CN)_6]_3$
$B$. $ZnCl_2 + 4NaOH \rightarrow$	$V$. $Na_2ZnO_2$
$C$. $2FeCl_3 + H_2S \rightarrow$	$II$. $FeCl_2$

Match List-$I$ with List-$II$ and select the correct code:

List-$I$	List-$II$
$A$. Ziegler-Natta	$i$. $Fe_4[Fe(CN)_6]_3$
$B$. Brown ring complex	$ii$. $[Fe(H_2O)_5NO]SO_4$
$C$. Prussian Blue	$iii$. $Al(C_2H_5)_3 + TiCl_4$
$D$. Turnbull Blue	$iv$. $Fe_3[Fe(CN)_6]_2$

Correct code is:

The equation which is balanced and represents the correct product$(s)$ is:

The correct option(s) about entropy $(S)$ is(are)
$[R =$ gas constant, $F =$ Faraday constant, $T =$ Temperature $]$
$(A)$ For the reaction, $M_{(s)} + 2H^{+}_{(aq)} \rightarrow H_{2(g)} + M^{2+}_{(aq)}$, if $\frac{dE_{cell}}{dT} = \frac{R}{F}$, then the entropy change of the reaction is $R$ (assume that entropy and internal energy changes in entropy and internal energy are temperature independent).
$(B)$ The cell reaction, $Pt_{(s)} \mid H_2(g, 1 \ bar) \mid H^{+}(aq, 0.01 \ M) \parallel H^{+}(aq, 0.1 \ M) \mid H_2(g, 1 \ bar) \mid Pt_{(s)}$, is an entropy driven process.
$(C)$ For racemization of an optically active compound, $\Delta S > 0$.
$(D)$ $\Delta S > 0$, for $[Ni(H_2O)_6]^{2+} + 3en \rightarrow [Ni(en)_3]^{2+} + 6H_2O$ (where $en =$ ethylenediamine).

The number of species having a square planar shape from the following is $........$.
$XeF_4$,$SF_4$,$SiF_4$,$BF_4^{-}$,$BrF_4^{-}$,$[Cu(NH_3)_4]^{2+}$,$[FeCl_4]^{2-}$,$[PtCl_4]^{2-}$