The equation which is balanced and represents | vedclass

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(D) Option $A$: The reaction $Li_2O + 2KCl \rightarrow 2LiCl + K_2O$ is thermodynamically unfavorable because $Li_2O$ is more stable than $K_2O$.Optio

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$CuSO_4 + 4KCN \rightarrow K_2[Cu(CN)_4] + K_2SO_4$

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(D) Option $A$: The reaction $Li_2O + 2KCl \rightarrow 2LiCl + K_2O$ is thermodynamically unfavorable because $Li_2O$ is more stable than $K_2O$.Option $B$: The reaction $[CoCl(NH_3)_5]^{2+} + 5H^+ \rightarrow Co^{2+} + 5NH_4^+ + Cl^-$ is balanced in terms of atoms and charge ($+2 + 5 = +7$ on left,$+2 + 5 - 1 = +6$ on right; wait,let's re-check: $Co^{2+} + 5NH_4^+ + Cl^-$ gives $+2 + 5 - 1 = +6$. The charge is not balanced).Option $C$: The reaction $[Mg(H_2O)_6]^{2+} + (EDTA)^{4-} \rightarrow [Mg(EDTA)]^{2-} + 6H_2O$ is balanced.Option $D$: The reaction $CuSO_4 + 4KCN \rightarrow K_2[Cu(CN)_4] + K_2SO_4$ is balanced: $Cu$ $(1)$,$S$ $(1)$,$O$ $(4)$,$K$ $(4)$,$C$ $(4)$,$N$ $(4)$ on both sides.

List-$I$	List-$II$
$(A). [Ag(CN)_2]^-$	$1. \text{Square planar, } 1.73 \, B.M.$
$(B). [Cu(CN)_4]^{3-}$	$2. \text{Linear, } 0 \, B.M.$
$(C). [Cu(CN)_6]^{4-}$	$3. \text{Octahedral, } 0 \, B.M.$
$(D). [Cu(NH_3)_4]^{2+}$	$4. \text{Tetrahedral, } 0 \, B.M.$
$(E). [Fe(CN)_6]^{4-}$	$5. \text{Octahedral, } 1.73 \, B.M.$

The equation which is balanced and represents the correct product$(s)$ is:

Similar Questions

$CuSO_{4(aq)}$ $\xrightarrow{H_2S \uparrow} M \downarrow$ $\xrightarrow[\text{Excess}]{KCN} N + O$
Then final products $N$ and $O$ are respectively.

Identify the correct set from the following table:

Total number of molecules/species from the following which will be paramagnetic is $........$
$O_2, O_2^{+}, O_2^{-}, NO, NO_2, CO, K_2[NiCl_4], [Co(NH_3)_6]Cl_3, K_2[Ni(CN)_4]$

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