The complex ion having minimum magnitude of $\Delta_{0}$ $(CFSE)$ is

  • A
    $[Cr(CN)_{6}]^{3-}$
  • B
    $[Co(NH_{3})_{6}]^{3+}$
  • C
    $[Co(Cl)_{6}]^{3-}$
  • D
    $[Cr(H_{2}O)_{6}]^{3+}$

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Given below are two statements:
Statement $I$: Presence of a large number of unpaired electrons in transition metal atoms results in higher enthalpies of their atomisation.
Statement $II$: $d_{xy} = d_{xz} = d_{yz} < d_{x^2-y^2} = d_{z^2}$ and $d_{x^2-y^2} < d_{xy} = d_{xz} = d_{yz}$ are the $d$-orbital splittings in $[Fe(H_2O)_6]^{3+}$ and $[Ni(Cl)_4]^{2-}$ complex ions respectively.
In the light of the above statements, choose the correct answer from the options given below:

Which complex shows the highest crystal field stabilisation energy?

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Match the electronic configurations in List-$I$ with appropriate metal complex ions in List-$II$ and choose the correct option.
[Atomic Number: $Fe=26, Mn=25, Co=27$]
List-$I$ List-$II$
$P$. $t_{2g}^6 e_g^0$ $1$. $[Fe(H_2O)_6]^{2+}$
$Q$. $t_{2g}^3 e_g^2$ $2$. $[Mn(H_2O)_6]^{2+}$
$R$. $e^2 t_2^3$ $3$. $[Co(NH_3)_6]^{3+}$
$S$. $t_{2g}^4 e_g^2$ $4$. $[FeCl_4]^{-}$
$5$. $[CoCl_4]^{2-}$

The correct order of ligands in the spectrochemical series is

Arrange the following ligands in the order of increasing field strength:
$H_2O$ $(I)$,$CO$ $(II)$,$NH_3$ $(III)$,$I^{-}$ $(IV)$,$F^{-}$ $(V)$

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