The compound statement $p \wedge (\sim p \wedge q)$ is

  • A
    $A$ tautology
  • B
    $A$ contradiction
  • C
    Equivalent to $p \wedge q$
  • D
    Equivalent to $p \vee q$

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Let $\Delta \in \{\wedge, \vee, \Rightarrow, \Leftrightarrow\}$ be such that $(p \wedge q) \Delta ((p \vee q) \Rightarrow q)$ is a tautology. Then $\Delta$ is equal to

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