The compound that has the largest H-M-H bond | vedclass

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(B) To determine the largest $H-M-H$ bond angle,we analyze the hybridization and lone pairs of the central atom in each molecule:$1$. In $H_{2}O$ ($O$

Vedclass · Accepted Answer

$CH_{4}$

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(B) To determine the largest $H-M-H$ bond angle,we analyze the hybridization and lone pairs of the central atom in each molecule:$1$. In $H_{2}O$ ($O$ is central atom),the hybridization is $sp^{3}$ with $2$ lone pairs,resulting in a bond angle of $104^{\circ}5'$.$2$. In $CH_{4}$ ($C$ is central atom),the hybridization is $sp^{3}$ with $0$ lone pairs,resulting in a perfect tetrahedral geometry with a bond angle of $109^{\circ}28'$.$3$. In $NH_{3}$ ($N$ is central atom),the hybridization is $sp^{3}$ with $1$ lone pair,resulting in a bond angle of $107^{\circ}$.$4$. In $H_{2}S$ ($S$ is central atom),the central atom is in the $3rd$ period,and the bond angle is close to $90^{\circ}$ due to the lack of hybridization (Drago's rule).Comparing these values,$CH_{4}$ has the largest bond angle of $109^{\circ}28'$.Thus,the correct option is $B$.

List-$I$ (Molecule)	List-$II$ (Shape)
$A$. $BrF_5$	$I$. $T$-shape
$B$. $H_2O$	$II$. See-saw
$C$. $ClF_3$	$III$. Bent
$D$. $SF_4$	$IV$. Square pyramidal

List-$I$ (species)	List-$II$ ($O-N-O$ angle)
$A$. $NO_2^+$	$1$. $180^{\circ}$
$B$. $NO_2$	$2$. $132^{\circ}$
$C$. $NO_2^-$	$3$. $115^{\circ}$
$D$. $NO_3^-$	$4$. $120^{\circ}$

The compound that has the largest $H-M-H$ bond angle $(M = N, O, S, C)$ is :

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In the structure of $SF_{4}$,the lone pair of electrons on $S$ is in ....

Match List-$I$ with List-$II$:

List-$I$ (Molecule) List-$II$ (Shape)

$A$. $BrF_5$ $I$. $T$-shape

$B$. $H_2O$ $II$. See-saw

$C$. $ClF_3$ $III$. Bent

$D$. $SF_4$ $IV$. Square pyramidal

What is the correct order of bond angles in the given molecules?

Match List-$I$ with List-$II$ and select the correct answer:

List-$I$ (species) List-$II$ ($O-N-O$ angle)

$A$. $NO_2^+$ $1$. $180^{\circ}$

$B$. $NO_2$ $2$. $132^{\circ}$

$C$. $NO_2^-$ $3$. $115^{\circ}$

$D$. $NO_3^-$ $4$. $120^{\circ}$

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