The compound that will react most readily with gaseous bromine has the formula

  • A
    $C_3H_6$
  • B
    $C_2H_2$
  • C
    $C_4H_{10}$
  • D
    $C_2H_4$

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The product of the reaction shown below is:

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Product '$A$' and '$B$' are respectively:
$CH_3-C(CH_3)=CH-C_6H_5 \xrightarrow{HBr/Peroxide} A$
$CH_3-C(CH_3)=CH-C_6H_5 \xrightarrow{HBr} B$

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Dehydration of ethanol gives

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