The compounds $A$ and $B$ in the following reaction are,respectively:
$Benzene$ $\xrightarrow{HCHO + HCl}$ $A$ $\xrightarrow{AgCN}$ $B$
$Benzene$ $\xrightarrow{HCHO + HCl}$ $A$ $\xrightarrow{AgCN}$ $B$
- A$A =$ Benzyl alcohol,$B =$ Benzyl cyanide
- B$A =$ Benzyl chloride,$B =$ Benzyl cyanide
- C$A =$ Benzyl alcohol,$B =$ Benzyl isocyanide
- D$A =$ Benzyl chloride,$B =$ Benzyl isocyanide
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Similar Questions
The increasing order of the boiling points of the major products $A$,$B$ and $C$ of the following reactions will be:
$C_2H_5Br$ $\xrightarrow{KCN} A$ $\xrightarrow{\text{Hydrolysis}} B$
The compound $A$ in the above reaction is
The compound $A$ in the above reaction is
Medium
View Solution$1,4$-dichlorohexane $(1 \ mole)$ + $NaI$ $(1 \ mole)$ $\xrightarrow{Acetone}$ Product of the reaction is
Difficult
View SolutionWhat are $X$ and $Y$ respectively in the following reactions?
What is $E$?
Cyclohexanone $\xrightarrow{Br_2 + CH_3COOH} A$ $\xrightarrow{Alc. KOH} B$ (Product with six-membered ring) $\xrightarrow[(2) H_2O]{(1) CH_3MgBr} C$ $\xrightarrow{H^{\oplus} + \Delta} D$ $\xrightarrow{HBr (1 \text{ mole})} E$
Cyclohexanone $\xrightarrow{Br_2 + CH_3COOH} A$ $\xrightarrow{Alc. KOH} B$ (Product with six-membered ring) $\xrightarrow[(2) H_2O]{(1) CH_3MgBr} C$ $\xrightarrow{H^{\oplus} + \Delta} D$ $\xrightarrow{HBr (1 \text{ mole})} E$
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