The compressibility of water is 4 times 10^{- | vedclass

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(A) The compressibility $C$ is defined as the reciprocal of the Bulk Modulus $K$,given by $C = \frac{1}{K} = \frac{\Delta V / V}{\Delta P}$.Rearrangin

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$0.4$

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(A) The compressibility $C$ is defined as the reciprocal of the Bulk Modulus $K$,given by $C = \frac{1}{K} = \frac{\Delta V / V}{\Delta P}$.Rearranging the formula to find the change in volume $\Delta V$,we get $\Delta V = C 	imes \Delta P 	imes V$.Given:Compressibility $C = 4 	imes 10^{-5} \ atm^{-1}$,Initial volume $V = 100 \ cm^3$,Change in pressure $\Delta P = 100 \ atm$.Substituting these values into the equation:$\Delta V = (4 	imes 10^{-5}) 	imes 100 	imes 100$$\Delta V = 4 	imes 10^{-5} 	imes 10^4$$\Delta V = 4 	imes 10^{-1} = 0.4 \ cm^3$.Therefore,the decrease in volume is $0.4 \ cm^3$.

The compressibility of water is $4 \times 10^{-5}$ per unit atmospheric pressure. The decrease in volume of $100 \ cm^3$ of water under a pressure of $100 \ atm$ will be ......... $cm^3$.

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