The coordinates of a point are (0, 1) and the | vedclass

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(C) Let the coordinates of the first point be $P(0, 1)$ and the second point be $Q(x, -3)$.Given that the distance between $P$ and $Q$ is $5$.Using th

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$\pm 3$

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(C) Let the coordinates of the first point be $P(0, 1)$ and the second point be $Q(x, -3)$.Given that the distance between $P$ and $Q$ is $5$.Using the distance formula: $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.$5 = \sqrt{(x - 0)^2 + (-3 - 1)^2}$.$5 = \sqrt{x^2 + (-4)^2}$.$5 = \sqrt{x^2 + 16}$.Squaring both sides: $25 = x^2 + 16$.$x^2 = 25 - 16 = 9$.$x = \pm 3$.Therefore,the abscissa of the other point is $\pm 3$.

The coordinates of a point are $(0, 1)$ and the ordinate of another point is $-3$. If the distance between the two points is $5$,then the abscissa of the other point is:

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