The correct Boolean operation represented by | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In the given circuit,the switches $A$ and $B$ are connected in parallel with the ground. When a switch is at position $0$,it is open,and when it i

Vedclass · Accepted Answer

$NAND$

Vedclass · Answer

(C) In the given circuit,the switches $A$ and $B$ are connected in parallel with the ground. When a switch is at position $0$,it is open,and when it is at position $1$,it is closed (connected to ground).$1$. If both $A=0$ and $B=0$,both switches are open. The current flows through the $LED$ $(Y)$,so $Y=1$.$2$. If $A=0$ and $B=1$,switch $B$ is closed (grounded). The current flows through the $LED$ $(Y)$,so $Y=1$.$3$. If $A=1$ and $B=0$,switch $A$ is closed (grounded). The current flows through the $LED$ $(Y)$,so $Y=1$.$4$. If $A=1$ and $B=1$,both switches are closed (grounded). The current bypasses the $LED$ through the switches to the ground,so $Y=0$.The truth table is:$A$$B$$Y$$0$$0$$1$$0$$1$$1$$1$$0$$1$$1$$1$$0$This truth table corresponds to the $NAND$ gate operation.

The correct Boolean operation represented by the circuit diagram shown is:

Similar Questions

The Boolean expression of the circuit given in the figure is

The output from a $NAND$ gate having inputs $A$ and $B$ given below will be:

For the following digital logic circuit,the correct truth-table is

If $X$ and $Y$ are the inputs, the given circuit works as . . . . . . .

The given symbol represents:

Vedclass Test Series

Exam Paper Generator

Online Exam Module