The correct graph between pressure (P) and de | vedclass

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(B) From the ideal gas law,we have $PV = nRT$.We know that the number of moles $n = \frac{m}{M}$,where $m$ is the mass and $M$ is the molar mass.Subst

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(B) From the ideal gas law,we have $PV = nRT$.We know that the number of moles $n = \frac{m}{M}$,where $m$ is the mass and $M$ is the molar mass.Substituting this into the equation,we get $PV = \frac{m}{M} RT$.Rearranging the terms,we get $P = \left(\frac{m}{V}\right) \frac{RT}{M}$.Since density $\rho = \frac{m}{V}$,the equation becomes $P = \rho \frac{RT}{M}$.At a constant temperature $(T)$,the gas constant $(R)$ and molar mass $(M)$ are also constant.Therefore,$P \propto \rho$,which represents a straight line passing through the origin.Thus,the correct graph is a straight line passing through the origin,which corresponds to graph $B$.

The correct graph between pressure $(P)$ and density $(\rho)$ of a gas at constant temperature is

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