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(A) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pair} = \frac{1}{2} (V - M - C + A)$,where $V$ is the nu

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$SO_3 < SnCl_2 < ClF_3 < XeF_2$

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(A) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pair} = \frac{1}{2} (V - M - C + A)$,where $V$ is the number of valence electrons,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge. Alternatively,we can use the structure: MoleculeLone pairs on central atom$SO_3$$0$$SnCl_2$$1$$ClF_3$$2$$XeF_2$$3$The increasing order of lone pairs is $SO_3 (0) < SnCl_2 (1) < ClF_3 (2) < XeF_2 (3)$.

The correct increasing order of the number of lone pairs of electrons on the central atom of $SnCl_2$,$XeF_2$,$ClF_3$,and $SO_3$ is:

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