The correct match about the reaction sequence | vedclass

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(A, B, C) Let us analyze the reactions of phenol:$1$. Reaction with phthalic anhydride in the presence of $H_2SO_4$ gives phenolphthalein. Thus,$A$ is

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$B$ is phenyl salicylate

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(A, B, C) Let us analyze the reactions of phenol:$1$. Reaction with phthalic anhydride in the presence of $H_2SO_4$ gives phenolphthalein. Thus,$A$ is phenolphthalein.$2$. Reaction with salicylic acid in the presence of $H^+$ gives phenyl salicylate (salol). Thus,$B$ is phenyl salicylate.$3$. The sequence $(i)$ $NaOH$,(ii) $CO_2, \Delta, P$,(iii) $H^+/H_2O$,(iv) $(CH_3CO)_2O$ is the Kolbe-Schmitt reaction followed by acetylation,which yields aspirin. Thus,$C$ is aspirin.$4$. Reaction with $PhN_2Cl$ in $NaOH$ gives $p$-hydroxyazobenzene. The structure $D$ shown is $p$-aminoazobenzene,which is incorrect.Therefore,the correct matches are $A$,$B$,and $C$.

Column-$I$ (Reaction)	Column-$II$ (Product and Reaction Name)
$A$. Phenol $+$ dilute $HNO_3$	$i$. Mononitrophenol,Nitration
$B$. Phenol $+$ Bromine water	$ii$. $2,4,6$-Tribromophenol,Bromination
$C$. Phenol $+$ $Na_2Cr_2O_7/H_2SO_4$	$iii$. Benzoquinone,Oxidation
$D$. Sodium phenoxide $+$ $CO_2$ followed by $H^+$	$iv$. Salicylic acid,Kolbe reaction

The correct match about the reaction sequence shown above is:

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