The correct order of atomic/ionic radii is

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Question

(A) In the $3d$-series,atomic radii generally decrease from $Sc$ to $Cr$ due to the increase in effective nuclear charge. Thus,the order $Sc > Ti > V

Vedclass · Accepted Answer

$Sc > Ti > V > Cr$

Vedclass · Answer

(A) In the $3d$-series,atomic radii generally decrease from $Sc$ to $Cr$ due to the increase in effective nuclear charge. Thus,the order $Sc > Ti > V > Cr$ is correct.For option $(b)$,the correct order is $Zn > Cu > Co \approx Ni$ because the increase in shielding effect balances the increase in nuclear charge.For option $(c)$,for isoelectronic species,the ionic radius increases as the negative charge increases and decreases as the atomic number increases. The correct order is $N^{3-} > O^{2-} > F^{-} > S^{2-} > Cl^{-}$.Therefore,option $(a)$ is the correct statement.

$E^{\Theta }$	$V$	$Cr$	$Mn$	$Fe$	$Co$	$Ni$	$Cu$
$(M^{2+}/M)$	$-1.18$	$-0.91$	$-1.18$	$-0.44$	$-0.28$	$-0.25$	$+0.35$

Similar Questions

Which one of the following is not a transition metal?

For the first row transition metals,the $E^{\Theta }$ values are:

$E^{\Theta }$ $V$ $Cr$ $Mn$ $Fe$ $Co$ $Ni$ $Cu$

$(M^{2+}/M)$ $-1.18$ $-0.91$ $-1.18$ $-0.44$ $-0.28$ $-0.25$ $+0.35$

Explain the irregularity in the above values.

Which of the following is $NOT$ an inner transition element?

$Mn^{2+}$ compounds are more stable than $Fe^{2+}$ compounds towards oxidation to their $+3$ state,because

Transition elements are:

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