The correct order of bond angles of the molec | vedclass

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Question

(D) The bond angles for the given molecules are as follows:$1.$ $HgCl_2$: Linear geometry ($sp$ hybridization),bond angle = $180^{\circ}$.$2.$ $SO_3$:

Vedclass · Accepted Answer

$HgCl_2 > SO_3 > SiCl_4 > NH_3$

Vedclass · Answer

(D) The bond angles for the given molecules are as follows:$1.$ $HgCl_2$: Linear geometry ($sp$ hybridization),bond angle = $180^{\circ}$.$2.$ $SO_3$: Trigonal planar geometry ($sp^2$ hybridization),bond angle = $120^{\circ}$.$3.$ $SiCl_4$: Tetrahedral geometry ($sp^3$ hybridization),bond angle = $109.5^{\circ}$.$4.$ $NH_3$: Trigonal pyramidal geometry ($sp^3$ hybridization with one lone pair),bond angle = $107^{\circ}$.Therefore,the correct order is $HgCl_2 > SO_3 > SiCl_4 > NH_3$.

List-$I$	List-$II$
$A$. $XeF_4$	$1$. Pyramidal
$B$. $XeF_6$	$2$. $T$-shape
$C$. $XeO_3$	$3$. Distorted octahedral
$D$. $XeOF_2$	$4$. Square planar

The correct order of bond angles of the molecules $SiCl_4$,$SO_3$,$NH_3$,and $HgCl_2$ is:

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What is the shape of $XeF_4$?

Which molecule $AX_3$,$AX_4$,$AX_5$,$AX_6$ is most likely to have a trigonal bipyramidal structure if $A$ has no lone pair?

Select the correct matching:

List-$I$ List-$II$

$A$. $XeF_4$ $1$. Pyramidal

$B$. $XeF_6$ $2$. $T$-shape

$C$. $XeO_3$ $3$. Distorted octahedral

$D$. $XeOF_2$ $4$. Square planar

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