The correct order of increasing s-character ( | vedclass

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(A) $I.$ $CO_3^{2-}$: Hybridization is $sp^2$,$s$-character = $\frac{1}{3} 	imes 100 = 33.33 \%$$II.$ $XeF_4$: Hybridization is $sp^3d^2$,$s$-charact

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$II < III < IV < I < V$

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(A) $I.$ $CO_3^{2-}$: Hybridization is $sp^2$,$s$-character = $\frac{1}{3} 	imes 100 = 33.33 \%$$II.$ $XeF_4$: Hybridization is $sp^3d^2$,$s$-character = $\frac{1}{6} 	imes 100 = 16.66 \%$$III.$ $I_3^-$: Hybridization is $sp^3d$,$s$-character = $\frac{1}{5} 	imes 100 = 20 \%$$IV.$ $NCl_3$: Hybridization is $sp^3$,$s$-character = $\frac{1}{4} 	imes 100 = 25 \%$$V.$ $BeCl_2$: Hybridization is $sp$,$s$-character = $\frac{1}{2} 	imes 100 = 50 \%$Comparing the percentages: $16.66 \% (II) Thus,the correct order is $II < III < IV < I < V$.

The correct order of increasing $s$-character (in percentage) in the hybrid orbitals of the following molecules/ions is :-
$I.$ $CO_3^{2-}$
$II.$ $XeF_4$
$III.$ $I_3^-$
$IV.$ $NCl_3$
$V.$ $BeCl_2$

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The correct order of increasing $s$-character (in percentage) in the hybrid orbitals of the following molecules/ions is :-$I.$ $CO_3^{2-}$$II.$ $XeF_4$$III.$ $I_3^-$$IV.$ $NCl_3$$V.$ $BeCl_2$