The correct order of second I.E. of C, N, O a | vedclass

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(D) The second ionisation energy $(I.E._2)$ is the energy required to remove an electron from a unipositive ion. The electronic configurations of the

Vedclass · Accepted Answer

$O > F > N > C$

Vedclass · Answer

(D) The second ionisation energy $(I.E._2)$ is the energy required to remove an electron from a unipositive ion. The electronic configurations of the unipositive ions are:$C^+ (Z=6): 1s^2, 2s^2, 2p^1$$N^+ (Z=7): 1s^2, 2s^2, 2p^2$$O^+ (Z=8): 1s^2, 2s^2, 2p^3$$F^+ (Z=9): 1s^2, 2s^2, 2p^4$Due to the stable half-filled $2p^3$ configuration in $O^+$,it requires more energy to remove an electron compared to $F^+$. Following the general trend of increasing $I.E.$ with increasing effective nuclear charge across a period,the order is $O > F > N > C$.

The correct order of second $I.E.$ of $C, N, O$ and $F$ is:

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