The correct order of stability for the follow | vedclass

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(A) The stability of an alkoxide ion is determined by the dispersal of the negative charge on the oxygen atom.$(A)$ $CH_3CH(NO_2)O^-$: The negative ch

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$(C) > (B) > (A)$

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(A) The stability of an alkoxide ion is determined by the dispersal of the negative charge on the oxygen atom.$(A)$ $CH_3CH(NO_2)O^-$: The negative charge is stabilized by the $-I$ effect of the $-NO_2$ group.$(B)$ $CH_2=C(NO_2)O^-$: The negative charge is in conjugation with the double bond and the $-NO_2$ group,providing resonance stabilization along with the $-I$ effect.$(C)$ $O_2N-CH=CH-O^-$: The negative charge is in extended conjugation with the double bond and the $-NO_2$ group. This allows for more effective delocalization of the negative charge compared to $(B)$,making it the most stable.Thus,the order of stability is $(C) > (B) > (A)$.

The correct order of stability for the following alkoxides is:
$(A)$ $CH_3CH(NO_2)O^-$
$(B)$ $CH_2=C(NO_2)O^-$
$(C)$ $O_2N-CH=CH-O^-$

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The correct order of stability for the following alkoxides is:$(A)$ $CH_3CH(NO_2)O^-$$(B)$ $CH_2=C(NO_2)O^-$$(C)$ $O_2N-CH=CH-O^-$