The correct order of the bond angles of the g | vedclass

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(B) In the group $15$ hydrides $(NH_3, PH_3, AsH_3, SbH_3)$, the central atom size increases down the group $(N < P < As < Sb)$.As the size of the cen

Vedclass · Accepted Answer

$SbH_3 < AsH_3 < PH_3 < NH_3$

Vedclass · Answer

(B) In the group $15$ hydrides $(NH_3, PH_3, AsH_3, SbH_3)$, the central atom size increases down the group $(N As the size of the central atom increases, the bond pair-bond pair repulsion decreases, and the electronegativity of the central atom decreases.This leads to a decrease in the bond angle as we move down the group.Therefore, the correct order of bond angles is $SbH_3 < AsH_3 < PH_3 < NH_3$.

Molecule	Geometry
$(a) SnCl_2$	$(i)$ Angular (or) Bent
$(b) XeF_4$	$(ii)$ See-saw
$(c) ClF_3$	$(iii)$ Square pyramidal
$(d) IF_5$	$(iv)$ $T$-shape
-	$(v)$ Square planar

The correct order of the bond angles of the given compounds is

Similar Questions

The correct sequence of decreasing bond angles for the following hydrides is:

Which one of the following compounds has a bond angle of nearly $90^{\circ}$?

Identify the incorrect statement related to $PCl_{5}$ from the following:

Match the following?
Molecule Geometry
$(a) SnCl_2$ $(i)$ Angular (or) Bent
$(b) XeF_4$ $(ii)$ See-saw
$(c) ClF_3$ $(iii)$ Square pyramidal
$(d) IF_5$ $(iv)$ $T$-shape
- $(v)$ Square planar

Which molecule has trigonal bipyramidal geometry?

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