The correct sequence which shows the decreasi | vedclass

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(D) All the given ions $(O^{2-}, F^{-}, Na^{+}, Mg^{2+}, Al^{3+})$ are isoelectronic,meaning they all have $10$ electrons.For isoelectronic species,th

Vedclass · Accepted Answer

$O^{2-} > F^{-} > Na^{+} > Mg^{2+} > Al^{3+}$

Vedclass · Answer

(D) All the given ions $(O^{2-}, F^{-}, Na^{+}, Mg^{2+}, Al^{3+})$ are isoelectronic,meaning they all have $10$ electrons.For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number) increases.$O^{2-}$ $(Z=8)$,$F^{-}$ $(Z=9)$,$Na^{+}$ $(Z=11)$,$Mg^{2+}$ $(Z=12)$,$Al^{3+}$ $(Z=13)$.Since the nuclear charge increases from $O^{2-}$ to $Al^{3+}$,the ionic radius decreases in the order: $O^{2-} > F^{-} > Na^{+} > Mg^{2+} > Al^{3+}$.

The correct sequence which shows the decreasing order of the ionic radii of the elements is:

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