The correct solubility order of AgF, AgCl, Ag | vedclass

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(B) The solubility of silver halides in water depends on the lattice energy and hydration energy. $AgF$ is highly soluble in water due to its high hyd

Vedclass · Accepted Answer

$AgI < AgBr < AgCl < AgF$

Vedclass · Answer

(B) The solubility of silver halides in water depends on the lattice energy and hydration energy. $AgF$ is highly soluble in water due to its high hydration energy. For the other silver halides ($AgCl$, $AgBr$, $AgI$), the lattice energy decreases as the size of the halide ion increases $(Cl^- However, the decrease in hydration energy is more significant than the decrease in lattice energy as we move from $Cl^-$ to $I^-$. Therefore, the solubility decreases in the order: $AgCl > AgBr > AgI$. Combining these, the overall order of solubility is $AgI < AgBr < AgCl < AgF$.

The correct solubility order of $AgF$, $AgCl$, $AgBr$, and $AgI$ in water is:

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