The correct statement regarding X and Y in th | vedclass

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(B) In the reaction forming $Y$,the catalyst used is Ziegler-Natta catalyst ($(C_2H_5)_3Al$ and $TiCl_4$) at low pressure and temperature,which produc

Vedclass · Accepted Answer

$X$ is $LDP$ and $Y$ is $HDP$

Vedclass · Answer

(B) In the reaction forming $Y$,the catalyst used is Ziegler-Natta catalyst ($(C_2H_5)_3Al$ and $TiCl_4$) at low pressure and temperature,which produces High Density Polyethylene $(HDP)$.In the reaction forming $X$,the initiator used is a peroxide $((C_6H_5COO)_2)$ at high pressure and temperature,which produces Low Density Polyethylene $(LDP)$.Therefore,$X$ is $LDP$ and $Y$ is $HDP$.$LDP$ is used in the insulation of electricity-carrying wires and in the manufacture of squeeze bottles.$HDP$ is used in the manufacture of containers like buckets,dustbins,bottles,and pipes.Thus,option $B$ is correct.

The correct statement regarding $X$ and $Y$ in the following set of reactions is:
$nCH_2=CH_2 \xrightarrow[(C_2H_5)_3Al, TiCl_4]{333-343 \ K, 6-7 \ atm} Y$
$nCH_2=CH_2 \xrightarrow[(C_6H_5COO)_2]{350-570 \ K, 1000-2000 \ atm} X$

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The correct statement regarding $X$ and $Y$ in the following set of reactions is:$nCH_2=CH_2 \xrightarrow[(C_2H_5)_3Al, TiCl_4]{333-343 \ K, 6-7 \ atm} Y$$nCH_2=CH_2 \xrightarrow[(C_6H_5COO)_2]{350-570 \ K, 1000-2000 \ atm} X$