The correspondence PQR leftrightarrow ZYX bet | vedclass

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Question

(A) Given that the correspondence $PQR \leftrightarrow ZYX$ is a similarity,we have $\Delta PQR \sim \Delta ZYX$.From the property of similar triangle

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(A) Given that the correspondence $PQR \leftrightarrow ZYX$ is a similarity,we have $\Delta PQR \sim \Delta ZYX$.From the property of similar triangles,the ratios of corresponding sides are equal:$\frac{PQ}{ZY} = \frac{QR}{YX} = \frac{PR}{ZX}$.We are given $\frac{PQ}{ZY} = \frac{5}{3}$ and $PR = 10$.Substituting these values into the ratio $\frac{PQ}{ZY} = \frac{PR}{ZX}$,we get:$\frac{5}{3} = \frac{10}{ZX}$.Cross-multiplying,we get $5 	imes ZX = 3 	imes 10$.$5 	imes ZX = 30$.$ZX = \frac{30}{5} = 6$.Therefore,the length of $ZX$ is $6$.

The correspondence $PQR \leftrightarrow ZYX$ between $\Delta PQR$ and $\Delta XYZ$ is a similarity. If $PQ : ZY = 5 : 3$ and $PR = 10$,find $ZX$.

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