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(A) The relationship between the critical angle $C$ and the refractive index $\mu$ of a medium with respect to air is given by the formula: $\sin C =

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$1.41$

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(A) The relationship between the critical angle $C$ and the refractive index $\mu$ of a medium with respect to air is given by the formula: $\sin C = \frac{1}{\mu}$.Given that the critical angle $C = 45^o$.Substituting the value into the formula: $\sin 45^o = \frac{1}{\mu}$.Since $\sin 45^o = \frac{1}{\sqrt{2}}$,we have $\frac{1}{\sqrt{2}} = \frac{1}{\mu}$.Therefore,$\mu = \sqrt{2}$.Calculating the value,$\mu \approx 1.414$,which is approximately $1.41$.

The critical angle of a medium with respect to air is $45^o$. The refractive index of the medium is

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