The current in a coil changes from 3 ,A to 1 | vedclass

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(C) The change in current in the coil is given by $\Delta I = I_f - I_i = 1 \,A - 3 \,A = -2 \,A$.The time interval is $\Delta t = 0.1 \,s$.The self-i

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$16 	imes 10^{-2} \,V$

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(C) The change in current in the coil is given by $\Delta I = I_f - I_i = 1 \,A - 3 \,A = -2 \,A$.The time interval is $\Delta t = 0.1 \,s$.The self-inductance of the coil is $L = 8 \,mH = 8 	imes 10^{-3} \,H$.The induced emf $(e)$ in the coil is given by the formula $e = -L \frac{dI}{dt}$.Substituting the values,we get $e = -(8 	imes 10^{-3} \,H) 	imes \frac{-2 \,A}{0.1 \,s}$.$e = 8 	imes 10^{-3} 	imes 20 \,V = 160 	imes 10^{-3} \,V = 16 	imes 10^{-2} \,V$.

The current in a coil changes from $3 \,A$ to $1 \,A$ in $0.1 \,s$ in a coil of self-inductance $8 \,mH$. The emf induced in the coil is

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